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A baseball thrown straight up, and its height as a function of time is given by the formula h=-16t2+32t. (where t is in seconds and height h is in feet).
i)Find the height of the ball when t=1 and t=3/2 seconds.
ii) Find the maximum height of the ball and the time at which the height is attained.
iii) At what time(s) is the height 7 ft achieved?
Added 3+ months ago:
Just in case there's some confusion, here's what I think I understand and what I'm unsure about... I need to plug (1) and (3/2) in for variable t separately. What I'm confused about is whether I'm looking to come up with two different heights for the ball...? Anyway, then... I guess I need to use my graphing calculator to find the max height of both of those separately? then I'm assuming my last problem can be found by plugging (7) in for t... I'd like to know if I'm at least on the right track. My instructor gave us an exam review but has not given solutions so I have no idea if I'm doing this correctly.
Added 3+ months ago:
Nevermind. figured it out...
It's not a physics class. It's a math 95 class, and I have a final coming up. If I were in physics I would agree, but since I am not I would love some actual assistance.