This is for math (algebra) and I can't figure out what values a and b must have. If the symbols are unclear this is what they say: Square of a+b = Square of a + Square of b
The only thing I have found out is that it is possible if a or b is 0, but is there another way?
What values must a and b have for this to be right?√a+b =√a +√b?
Details:
Responses (2)
ok, we have;
this problem is related to the pythagorean theorem so;
a+b^2 = a^2+b^2
well;
let say a+b^2= 10, a^2=6 and b^2=x.
by pythagorean theorem; AC^2=BC^2+BA^2
<=> a+b^2=a^2+b^2.
10^2=6^2+x^2
100-36=x^2
x=square root of 64=8
thus;
its just to apply "de square of de measure of the hypotenuse(a+b^2) of a triangle = the sum of the square of the measure of the other two sides(a^2+b^2). tanku
CORRECTION (2nd line):
√(a + b) =√a + √b ;; you want a and b: square but do it by the rules:
( √(a + b))² = (√a + √b)²
a + b = a + 2√a√b + b ;; subtract (a + b)
2√a√b = 0
And that's only true, if a or b equal 0. So, congratulations: The Meg-Lian conjecture is correct ;)