a 10 ohm resistor and a 50 ohm resistor are wired in series so that 3A flow through the curcuit. A third resistor is added so that the current drops to 2A.
Answers (1)
You have to assume that the applied voltage remains constant or there is no answer.
The two resistors add up to 60 ohms, so the applied voltage is 60Ω x 3A = 180V.
Next we have 180V/2A = 90Ω so the third resistor is 30Ω.
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