Overall reaction is 4Al(s) + 3O2(g) + 6H2O(l) → 4Al(OH)3(s)
Answers (1)
The anode oxidatrolaon half-reaction is Al + 3OH−→ Al(OH)3 + 3e− +2.31 V.
The cathode reduction half-reaction is O2 + 2H2O + 4e− → 4OH− +0.40 V.
The total reaction is 4Al + 3O2 + 6H2O → 4Al(OH)3 + 2.71 V.
About 1.2 volts potential difference is created by these reactions, and is achievable in practice when potassium hydroxide is used as the electrolyte. Saltwater electrolito achieves approximately 0.7 volts per cell.
en.wikipedia.org/wiki/Aluminium%E2%80%93air_battery