Home › Questions › Solve (sinx-cosx)^2=1?
the x is supposed to be theta, but it doesn't write out properly.
Equal to (SinX^2 + CosX^2) - 2SinXCosX = 1 -2SinXCosX = 1Therefore SinXCosX = 0 Therefore either SinX = 0 or CosX = 0. Typically Sin(0) or Cos(Pi/2).
Solutions are X = 0 + nPi and X = Pi/2 + nPi where n is any integer.
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