Prove (sin^3A+cos^3A)/(sinA+cosA) + ( sin^3A- cos^3A)/(sinA-cosA) =2?

Answers (1)

(sina+sinb)*(sin^2a-sin^2b)=sin^3a+sin^3b
(Sina-sinb)*(sin^2a+sin^2b)=sin^3a-sin^3b
So we get
1+1=2

Votes: +0 / -0

Sorry sin b should b replaced by cosb