PhiBonacci

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What is the quotient of the question below in lowest terms?

Question posted by PhiBonacci 3+ months ago | 2 answers | | Open

Related topics: below, question, algebra

PhiBonacci's answer: There are four binomials to factorise. c^2 - c - 2 = (c - 2)(c + 1) c^2 - 1 = (c - 1)(c + 1) c^2 + 3c + 2 = (c + 2)(c + 1) c^2 - 3c + 2 = (c - 2)(c - 1) ------- The whole thing now looks like this: (((c - 2)(c + 1)) / ((c - 1)(c + 1))) / (((c ...

What is x if 8x+4=x-3?

Question posted by PhiBonacci 3+ months ago | 4 answers | | Open

Related topics: maths, algebra

PhiBonacci's answer: 8x + 4 = x - 3 ;; subtract 4 from both sides 8x + 4 - 4 = x - 3 - 4 ;; tidy up 8x = x - 7 ;; subtract x from both sides 8x - x = x - x - 7 ;; tidy up 7x = -7 ;; divide by 7 (7/7)x = -7/7 1x = -1 x = -1. Check: 8 ⋅ -1 + 4 = -1 - 3 -8 + ...

How do I find the line that passes thru (4,3) ( -2,5)?

Question posted by PhiBonacci 3+ months ago | 2 answers | | Open

Related topics: line, algebra

PhiBonacci's answer: slope m = (5 - 3) / (-2 - 4) = 2 / -6 = 1 / -3. Point-slope form of a linear equation: y - 3 = ( -1/3)(x - 4) ;; inserting coordinates of P1( 4, 3) in y - y1 = m(x - x1) y = -x/3 + 4/3 + 3 = -(1/3)x + (4 + 1/3);; slope (y)intercept form, which ...

How do I solve this problem x^2 + x - 3/4 = 0?

Question posted by PhiBonacci 3+ months ago | 3 answers | | Open

Related topics: broken, down, step, problem, algebra

PhiBonacci's answer: x^2 + px + q = 0 : x1,2 = -p/2 +- sqrt( (p/2)^2 - q) Thus: x^2 + x - 3/4 = 0 x1,2 = -1/2 +- sqrt( 1/4 + 3/4) x1 = -3/2 x2 = 1/2 (x + 3/2)(x - 1/2) = 0

Find the sum of the multiples of 3 or 7 under 875?

Question posted by PhiBonacci 3+ months ago | 1 answers | | Open

Related topics: natural, number, multiple, under, below, example, numbers, algebra

PhiBonacci's answer: DIV = integer division operator R = remainder 875 DIV 3 = 291, R=2, so there are 291 multiples m of 3 that meet the condition 3m < 875. 875 DIV 7 = 125, R=0 so in order to meet the condition we have to subtract 1. There are 124 multiples of 7, ...

Simplify cos theta sec theta + cos theta tan theta?

Question posted by PhiBonacci 3+ months ago | 1 answers | | Open

Related topics: tan, math, maths, algebra

PhiBonacci's response: As sec(θ) = 1 / cos(θ) and tan(θ) = sin(θ) / cos(θ): cos(θ) sec(θ) + cos(θ) tan(θ) = cos(θ) / cos(θ) + (cos(θ) sin(θ)) / cos(θ) = 1 + sin(θ).

Number from 1 to 9 to create 2 coordinates with a slope of 8. You may only use a number once?

Question posted by PhiBonacci 3+ months ago | 2 answers | | Open

Related topics: number, slope, numbers, algebra

PhiBonacci's answer: I think, you want to create 2 pairs of x/y-coordinates: P1( 2, 1), P2( 3, 9), or P1( 3, 1), P2( 4, 9), ... P1( 7, 1), P2( 8, 9).

The width of a rectangle is 3 less than its length. if the length is multiplied by 2 and the width?

Question posted by PhiBonacci 3+ months ago | 2 answers | | Open

Related topics: perimeter, length, math, algebra

PhiBonacci's answer: W = width L = length W = L - 3 New length = 2L New width = L - 3 + 4 = L + 1 2 * 2L + 2(L + 1) = 50 ;; new perimeter P = 50 4L + 2L + 2 = 50 ;; solve for L 6L = 48 L = 8. New dimensions: 2L = 16 -> new length u = 16 L + 1 = 9 -> new ...

Q line passes through points with coordinate(3,7)and (-2,-3). What is the equation of the line?

Question posted by PhiBonacci 3+ months ago | 1 answers | | Open

Related topics: line, multiple, point, choice, equations

PhiBonacci's comment: Option 1) y = 2x + 1 is your answer. I didn't notice the "-" in 3) y = -2x + 1 at first sight. Spaces do increase readability.

Grandma and grandpa had six children. each of those children grew up and had four children of their?

Question posted by PhiBonacci 3+ months ago | 1 answers | | Open

Related topics: children, people, house, grandma, dinner, thanksgiving, grandpa

PhiBonacci's answer: All children were female and reproduced via parthenogenesis. So, no fathers except great-grandpa at the table: Grandma and grandpa (2) had six children(6). each of those children grew up and had four children of their own(4*6). those children all ...