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... cross roads of width 5m run at right angles through the center of this park
What exactly is your question?Assumption:Area covered by the cross roads:
75*5 + 60*5 - 5*55 * (75 + 60 - 25)5 * 110 = 550m²
Sorry, a typo sneaked in. I'll do it again:
75*5 + 60*5 - 5*55 * (75 + 60 - 5)5 * 130 = 650m²
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Sorry, a typo sneaked in. I'll do it again:
75*5 + 60*5 - 5*5
5 * (75 + 60 - 5)
5 * 130 = 650m²