Math Homework help please?

Solve by factoring:
5x² + 2x = 0

x ( 5x + 2 ) = 0
Obviously x1 = 0

5x + 2 = 0
5x = -2
So:
x2 = -2/5 = -0.4

system of equations:

1) 2x + 5y = 6
2) 3x + 2y = -2

Subtract eq. 1) from 2):
3x + 2y = -2
- (2x + 5y = 6)
= ( x - 3y = -8)
= ( x = 3y - 8)
Now we can substitute x by the term (3y - 8) in any of the above equations:
1) 2(3y -8) + 5y = 6
6y -16 +5y = 6
11y = 22
y = 2
Or take eq. 2:
2) 3(3y -8) +2y = -2
9y - 24 +2y = -2
11y = 22
y = 2

Finally insert 2, the value of y, in any of the above equations to get x:
1) 2x + 10 = 6
x = -2
2) 3x + 4 = -2
3x = -6
x = -2