Limit x tending to 0 d/dx square root of (1-cos2x)?

Question

Limit x tending to 0       d/dx  square root of (1-cos2x)?

Answer

it is square root na so ans is 
                                                

            d/dx sqre rot of (1-cos2x) = 1/ 2 Xsquare root of (1- cos2x) X 2sin2x
                      
              here 2 & 2 get cancle

                                 answer will b 
                                                         1/ (sqre root of 1-cos2x) X sin2x


                        bcoz d/dx(sqre rot of x) = 1/ 2  X sqre root of x

Limit x tending to 0 d/dx square root of (1-cos2x)?

Responses (2)