A storm is moving toward your house at a speed of 20km/hr. It is now 60 km away from your house. In what time will the storm reach your house? Do I do T= d/s ?
In what time will the storm reach your house? Math help!!! d/s?
- Posted:
- 3+ months ago by Cassidy123
- Topics:
- speed, storm, math, time
Details:
Answers (2)
All you have to do is divide 20 by 60.
If it's moving at a speed of 20km/h, and it's 60km away right now, we divide the speed it's moving at by how far away it is now, and we get 0.33.
0.33 into an hour (which is 60 minutes) would be just over half an hour.
Or, we could look at it from the opposite way, and divide 60 by 20 to get 3. (As in 3 hours)
I was only doing simple math. Not everyone is a fan of the subject.
If
T = time
d = distance
s = speed
then your equation T=d/s is correct.
If you are biking at a constant speed of 20km/hr and you do this for 3 hours, how many kilometers will you have covered? Obviously
20km/hr * 3hr = 60km
And as this is an equation and not a wizard spell you get what you want with simple rearrangements :
20km/hr * 3hr = 60km ;;; divide by the speed
3hr = 60km / (20km/hr) ;;; divide the unit-stuff by multiplying the inverse
3hr = 3 (km/1)*(hr/km)
3hr = 3 (km*hr)/km ;;; km just cancels out
3hr = 3hr ;;; dividing a distance by a speed really gives you the corresponding time!
(20km/h) / 60km = 1 / 3h = 1 / 10800sec = 9.26*10^-5 Hz
which just tells you that at a speed of 20km/h the squall line covers the 60km 1/3 times per hour. Well, that would'nt be my first choice to express a time span ;)