If the line segment joining the points A(2,1) and B(5,-8) is trisected at the points p and Q findthe

Let P and Q be the point of rejection of AB, AP=PQ=QB
Now AP:PB=1:2
A=2,1andB=5,-8
therefor
P(x,y)=(m1.x2+m2x1/m1+m2),(m1.y2+m2.y1/m1+m2)
(5+4/3),(-8+2/3)=(3,-2)
llly, now AQ:QB =2:1 A=(2,1) B=(5,-8)
Q(x,y)=(m1x2+m2x1/m1+m2,m1y2+m2y1/m1+m2)
Q(x,y)=(2(5)+1(2),/2+1,2(-8)+1(1)/2+1)
=(10+2/3,-16+1/3)
=(12/3,-15/3)
=4,-5
therefor coordinates of P=(3,-2) ,Q=(4,-5)