If a+a+a =6 a+b = 7 c-b = 76 then find a+b+c = ?

The answer would be 88. If a+a+a=6, then that can be rewritten as 3a=6. From there, you divide 6 by 3, and so a is equal to 2.

If a+b=7, and a=2, then 2+b=7. Working the equation algebraically, you would subtract 2 from 7, and so b equals 5.

From this point, you can say that if c-b+=76 and b=5, then 76+5 must equal c, and so c= 81.

Finally, you can add the numbers together. a+b+c, which is also 2+5+81, equals 88.