if I have 10 dark chocolates and 7 milk chocolates and I take out 2 chocolates what is the probability percentage of me taking out 2 different types of chocolates
I have 10 and 7 and I take out 2 what is the probability percentage of me taking out 2 different?
- Posted:
- 3+ months ago by emountford
- Topics:
- dark, chocolate, different, milk, taking, type, percentage, probability
Details:
Responses (2)
Correction: There are 17 possibilities for the first choice and 16 for the second choice. Seven combinations qualify, so the odds are 7/(17 x 16) = 0.025735294 = 2.5735294%
You might have noticed this field can be very confusing.
Split it to two independent scenarios, then add up their probabilities:
1) Dark is picked, followed by white.
2) White is picked, followed by dark.
Assuming uniform distribution of the selection (would not recommend when involving chocolate!), and that the piece is removed permanently,
P = (10 / 17) * (7 / 16) + (7 / 17) * (10 / 16) ~ 51.471%.
Now, test in an environment you can count - 2 dark, 1 milk (or preferably 3 and 2), and name them 1, 2, 3.
P = 2 / 3
Actual scenarios are: 12 (bad), 13, 21 (bad), 23, 31, 32 - total of 4 / 6, matching the above.
Wow, you actually picked jv's answer. Well, failure's all yours, mate.
I hope you know percent is just 100 times the fraction.
1/17 = 0.058823529 = 5.8823529%