How many moles of fe are present in 30g of rust?

Answers (1)

The molar mass of Fe2O3 = 2 x Fe (2 x 55.85) + 3 x O (3 x 16.00) = 159.7 g/mole. 31.0 g Fe2O3 x (1 mole Fe2O3 / 159.7 g Fe2O3) .

Votes: +0 / -0