Answers (5)
"math" has 4 different letters.
Let n = 4
an arrangement of a subset consisting of 3 letters out of the set of 4 letters shall be k.
So it is n! (which is the factorial 1*2*3*4 = 24) over (n - k)! which happens to be (4 - 3)! = 1! = 1. So there are 24 different arrangements possible.