At 520 K, the value of Kc is 4.6x10^-6 for the reaction 2NOCl (g) = 2 NO(g) + Cl2 (g). If 4.0 moles of pure NOCl and 2.0 moles of pure Cl2 are placed in a 4.0L container at 520 K, calculate the amount of NO in the flask at equilibrium.