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One child is twice the age of another. In 7 years the younger child will be 2/3 the age of the older child. Find their present ages.
Let x be the younger kid's age. Let y be the older one's age.
I) y=2*xII) x+7=2/3*(y+7)
-> x+7=2/3*(2*x+7) -> x+7=4/3*x +14/3 -> 21/3-14/3=(4/3-3/3)*x ->7/3=x/3 -> x=7 -> y=14
3 6 1/24 75 86 9 2/3 They are 3 and 6 right now.
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