This problem was given to find displacement (when the object is constantly accelerating). I'm still VERY NEW to physics and advanced math, but the two seperate answers are a result of me going the only two routes I figured I could. Are either one correct? If so which? If not what is it? And regardless of the answer, how EXACTLY are you suppose to figure it out? Show the work please, and try to simplify it as much as possible!
D= (5m/s)(3s)+(1/2)(2m/s/s)(3s).. I've got two answers: 18m and 24m, which is right?? Show work!?
Details:
Added 3+ months ago:
The equation I had to work with represented displacement as: d=Vot+1/2at^2
Added 3+ months ago:
Note that at the end: (2m/s/s)(3s) was actually meant to be: (2m/s/s)(3s)^2
Added 3+ months ago:
Note that at the end: (2m/s/s)(3s) was actually meant to be: (2m/s/s)(3s)^2
Responses (1)
You need to work on presentation.
D = (5m/s) x 3s + (1/2)(2m/s^2)(3s)^2 derived from d = at + (1/2)at^2
"Per second per second" is written as "per square second" because those two expressions are mathematically identical, but one expressions avoids the confusion of order, which is what caused your problem. Next, you analyze the dimensions. You have m+m above the fraction line, so that appears in the answer. You have s below the line and again above the line so that cancels. Then you have s^2 below the line and again above the line so that cancels. The answer is a distance in meters. Now you just do the arithmetic.
5 x 3 + 2/2 x 3 x 3 = 15 + 9 = 24m