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... KING(y)) ∧ BALD
∃x (KING(x) ∧ ¬∃y (x ≠ y ∧ KING(y)) ∧ BALD There's something missing like:∃x (KING(x) ∧ ¬∃y (x ≠ y ∧ KING(y)) ∧ BALD (x))In English:There is only one king and he is bald.
A parenthesis got int the wrong place: Correction:
∃x (KING(x) ∧ ¬∃y (x ≠ y ∧ KING(y))) ∧ BALD (x)
Sorry.
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A parenthesis got int the wrong place: Correction:
∃x (KING(x) ∧ ¬∃y (x ≠ y ∧ KING(y))) ∧ BALD (x)
Sorry.