You have 2 matching volumes of the same ideal gas separated by a partition. The gas in both volumes is subject to standard temperature and pressure.
What is the change in entropy of this system if the partition is then removed?
Calculate the change in entropy?
- Posted:
- 3+ months ago by StarkIndu...
- Topics:
- gas, temperature, standard, pressure, volume, entropy, subject, partition
Details:
Added 3+ months ago:
I think the answer is Nkln(4) or nRln(4) or is this a test of conceptual understanding and the answer just zero?
Added 3+ months ago:
As I understand it mixing different ideal gases.
ΔS1=Nkln((vf)/vi) ΔS2=Nkln((vf)/vi) and ΔS=ΔS1+ΔS2 the answer should be ΔS=Nkln(4) then. It is as a mixing of any 2 different ideal gases would be. The fact that they are the same has no bearing?
