Al+(Cr2O7)2- = Al3+ + Cr3+
[al3+]=0.01M
[(cr2o7)2-]= 0.1M
[cr3+]=0.001M
find the E cell if we add Naoh to each electrode until al(oh)3 precipitates pH=8
KPT of al(oh)3=5 * 10 -33
Eal=-1.66 V
Ecr=1.33V