A train moves with a uniform velocity of 36 kmh-1 for 10 s. Find the distance travelled by it?
- Posted:
- 3+ months ago by malikalih...
- Topics:
- train, uniform, distance, velocity
Answers (2)
You need help with your Algebraic Physics homework? I'll help because physics is my life, but I suggest studying problems like this as boring as it sounds. Getting the answer online isn't the best idea, you won't learn much.
Now, 36KmH is 36 kilometers (36000 Meters) per hour. We need to find out how far it goes every second. Hour to minutes, then to seconds is 1 x 60 x 60 or 3600 seconds. Now, 36000 meters every 3600 seconds is a basic math problem. 36000 divided by 3600, which is 10. That means the train travels 10 meters a second. 10 meters a second for 10 seconds is 10 x 10, which is 100.
The answer is 100 Meters.
Good luck with the test!
A conversion factor is a fraction equal to 1. You are given that one hour equals 60 minutes so you can write that as hr/60min=1 or 60min/hr=1 whichever works for you and drop it into an equation anywhere and it only changes the units.
ANSWER = You write this first so it looks like you know what you are doing. That gives you a bit of time to figure out what to do next.
ANSWER = 36kmh^-1 x 10s x h/3600s (We use Shift-6 for exponents.)
Ok, now we check everything. This is called sanity check and it is especially important in chemistry and physics where you might have a dozen or so conversions in a single equation. We have h below the fraction line and again above, so that cancels. We have s above the line and again below, so that cancels. We have m above the line and that appears in the answer, which is what we want. When you are sure everything is right, multiply all the numbers above the line and divide by all the numbers below the line.
ANSWER = 36kmh^-1 x 10s x h/3600s = 100 m/s
By the way, this is not including friction or air resistance, but I doubt your problem is that complex. I am assuming the train is moving at a constant speed.