A space iron ball dropped in it so that the water level increases to 6.75cm find the radius of the ball??
Answers (1)
Now you just can't stand misspellings in this subject. It does not matter what the water level went to, you need to know how much the water level rose. So you might say your question is all wet.
Let's say the water level rose 6.75 cm. That means the volume of the sphere equals the volume of water displaced (since an iron ball sinks).
v = hπr^2 = 6.75 x π x 144 = 3053.628 cm^3 volume of cylinder
v = (4/3)πr^3 volume of a sphere
3053.628/(4/3)π = r^3
r = (729)^(1/3) = 9 <-- ANSWER
This assumes the sphere was completely covered by the water. If the water was not at least 18 cm deep, the analysis would have to be more clever.