the boy age is as same as the his father age and the addition of both the ages is 126 and the father age is as same age as his boy and the addition of these two ages is 38 then what is the age of father and boy.
Responses (1)
First, get out of the habit of hitting the Shift key just because you start a new line. A is not the same as a and a math program will not tell you that you misspelled something, it will just give you goofy results.
Second, add spaces to improve readability.
a + b = 126
a - b = 38
You have two linear equations. They look like this: www.wolframalpha.com/input/?i=plot+a+%2B+b+%3D+126,+a+-+b+%3D+38
Where they cross, the values of a and b satisfy both equations simultaneously, so it is called a simultaneous system. There are two ways to find that point. Substitution is when you solve one equation for one variable and substitute that into the other equation.
a - b = 38 therefore a = 38 + b
a + b = 126 therefore 38 + b + b = 126
2b = 88
b = 44
a = 82
Elimination is when you add the equations in a way to eliminate one variable. Otherwise the process is the same.
a + b = 126
a - b = 38
------------ ADD
2a ... = 164
a = 82 <-- SAME ANSWER
the previous question was something wrong.....above one is the correct
That makes no sense.
when son's age will father's age then addition of ages is 126, when father's age was the son's age then addition of their ages is 38 find their present ages?