solve each of the folling systems of equations.
Answers (2)
Given that 3x+y=-1 - (1)
2x-3y=8 - (2)
Now multiply the equation (1) with 3 then we get
9x+3y=-3 -(3)
Now add equations (2) &(3) then
11x=-11impliesx=-1
Now substitute the value of x in eaquation(1) then
y=2
Therefore x=-1 and y=2.
In equation (2) if it is -8 then do the same procedure.
a) 3x + y = -1
b) 2x - 3y = -8
9x + 3y = -3 ;; which is eqn. a) times 3. Add b)
(9x + 2x) + (3y + -3y) = (-3 + -8)
11x = -11
x = -1 ;; insert into a) or b) to get y:
a)
-3 + y = -1
y = 2.
or b)
-2 - 3y = -8
-3y = -6
y = 2.
So, the graph of the 2 equations will intersect at P( -1, 2).