(2) A student walks 160 m N and then walks 210 m E farther in 140 s . What is the magnitude of the?

The way this question is phrased makes me think it wants the distance covered (as the crow flies) divided by the time. His speed (which is a scalar quantity) is 370m/140s or about 2.6m/s. However it asks for velocity (which is a vector quantity) so we have to work out his actual distance covered from the starting point. If we use 160 and 210 as the adjacent and opposite of a right-angled triangle then do a bit of pythagoras to it, the total distance is the square root of 160² + 210², which comes to 264m. Therefore his velocity is 264m/140s, which is 1.82m/s (and not the 2.6m/s they were trying to trick you into).